**Load calculation on column, Beam & Slab**:

For calculations total load on columns, Beam, Slab we must know about various load coming on the column.

### Various **Load calculation on column, Beam & Slab**:

1) Column Self Weight X Number of floors

2) Beams Self Weight per running meter

3) A load of walls per running meter

4) The total load on Slab (Dead load + Live load + Self-weight)

Besides this above loading, the columns are also subjected to bending moments that have to be considered in the final design.

The most effective method for designing structure is to use advanced structural design software like **ETABS or STAAD Pro.**

These tools are reduced laborious and consuming method of manual calculations for structural design, this is highly recommended nowadays in the field.

for professional structural design practice, there are some basic assumptions we use for structural loading calculations.

**Read More: ****RCC COLUMN DESIGN**

**For ****Column:**

we know that the Self-weight of Concrete is around **2400 kg/m3,** which is equivalent to 240 kN and the Self-weight of Steel is around **8000 kg/m3.**

So, if we assume a column size of 230 mm x 600 mm with 1% steel and 3 meters standard height, the self-weight of the column is around 1000 kg per floor, that id equal to **10 kN. **

**Volume of Concrete = 0.23 x 0.60 x 3 =0.414m³****Weight of Concrete = 0.414 x 2400 = 993.6 kg****Weight of Steel (1%) in Concrete**=**0.414x 0.01 x 8000****= 33 kg****Total Weight of Column = 994 + 33 = 1026 kg****= 10KN**

While doing calculations, we assume the self weight of columns is between **10 to 15 kN per floor.**

**Load calculation on column, Beam & Slab**:

**For Be**am:

We adopt the same method of calculations for beam also.

we assume each meter of the beam has dimensions of **230 mm x 450 mm** excluding slab thickness.

**Assume each (1m) meter of the beam has dimension **

**230 mm x 450 mm excluding slab.****Volume of Concrete = 0.23 x 0.60 x 1 =0.138m³****Weight of Concrete = 0.138 x 2400 = 333 kg****Weight of Steel (2%) in Concrete**=**= 0.138 x 0.02 x 8000****= 22 kg****Total Weight of Column = 333 + 22 = 355 kg/m****= 3.5 KN/m**

So, the self-weight will be around **3.5 kN** per running meter.

**Read More: ****ESTIMATION OF A BUILDING WITH PLAN**

**For Walls**:

we know that the Density of bricks varies between **1500 to 2000 kg per cubic meter. **

For a 6 inch thick Brick wall of 3-meter height and a length of 1 meter,

The load / running meter to be equal to **0.150 x 1 x 3 x 2000 = 900 kg, **

which is equivalent to **9 kN/meter. **

This method can be adopted for load calculations of Brick per running meter for any brick type using this technique.

For aerated concrete blocks and autoclaved concrete blocks, like Aerocon or Siporex, the weight per cubic meter is between **550 to 700 kg **per cubic meter.

if your are using these blocks for construction, the wall loads per running meter can be as low as **4 kN/meter**, use of this block can significantly reduce the cost of the project.

**For Slab**:

Let, Assume the slab has a thickness of **125 mm. **

So, the Self-weight of each square meter of the slab would be

**= 0.125 x 1 x 2400 = 300 kg which is equivalent to 3 kN.**

Now, If we consider the Finishing load to be 1 kN per meter and superimposed live load to be **2 kN** per meter.

So, from the above data, we can estimate the slab load to be around **6 to 7 kN per square meter.**

### The factor of Safety:

In the end, after calculating the entire load on a column, do not forget to add in the factor of safety, which is most important for any building design for safe and convenient performance of the building during his design life duration.

**As Per IS 456:2000, the factor of safety is 1.5.**

**Read More: **

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Very useful tips its help every engineer in their field.please send that type of tips for civil engineering frequently.

Good products

#Useful

Indeed these tips are very useful & helpful in the working field

if we have 4 columns in a floor , should we multiple 10kn x 4 columns to find load? or we can put 10 kN for one floor randomly?

Interestingly this article has the same errors as seen on another post from 2011